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Find the probability that a randomlyselected point within the circle fallsin the red shaded area (square).r= 4 cm412 cm[? ]%Round to the nearest tenth of a percent.Enter

User Wanderso
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1 Answer

1 vote

Answer:

63.7%

Step-by-step explanation:

To know the probability, we need to calculate the area of the circle and the area of the square.

The area of the circle is equal to:


A_c=\pi\cdot r^2

Where r is the radius of the circle and π is approximately 3.14. So, the area of the circle is:


\begin{gathered} A_c=3.14*4^2 \\ A_c=3.14*16 \\ A_c=50.24 \end{gathered}

On the other hand, the area of the square is equal to:


\begin{gathered} A_s=\text{Base}* Height \\ A_s=4\sqrt[]{2}*4\sqrt[]{2} \\ A_s=32 \end{gathered}

Now, the probability that a randomly selected point within the circle falls in the square area is equal to the ratio of the areas calculated above. So, the probability is:


P=(A_s)/(A_c)=(32)/(50.24)=0.637=63.7\text{ \%}

Therefore, the answer is 63.7%

User Gowtham Raj
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3.2k points