7)
The given equation of line is y = -5 and the passing point of the new line is (11,15)
The new equation of the line is perpendicular to the y = -5 and passes through (11,15)
The standard form of a line is y = mx + b where m is the slope
So, the given line can be express as;
y = (0)x + (-5)
Thus the slope of the given line is 0
The slopes of two perpendicular lines in the plane is - 1
Let the slope of the new line express as n and the slope of the given line is 0, then the product of 0 and n must be equal to -1
(0)n = -1
n = -1/0
n = undefined
The line y = -5 express as;
Since, the line y = -5 is parallel to the x axis, so the line perpendicular to the y = -5 must be in the form of x = k
As, the line is passes through the (11,15), i.e., x = 11 and y = 15
So, the equation of the line is x = 11
Answer, x = 11