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Suppose you like to keep a jar of change on your desk currently at the jar contains the followingWhat is the probability that you reach into the jar and grab a penny and then without replacement a dime? Express your answer as a fraction or decimal number rounded to four decimal places

Suppose you like to keep a jar of change on your desk currently at the jar contains-example-1
User David Bern
by
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1 Answer

2 votes
Answer:

The probability of a penny and then without replacement a dime = 7/376

Step-by-step explanation:

Given:

A jar contains:

6 Pennies, 7 Dimes, 16 Nickels, and 19 Quarters

To find:

the probability when you reach into the jar and grab a penny and then without replacement a dime

Total coins = 6 + 7 + 16 + 19

Total coins = 48

Probability of picking a penny = number of pennies/total coins

Probability of picking a penny = 6/48

Probability of picking a dime after a penny without replacement:

Since we are not replacing the first pick, the total coins will reduce by 1

Total coin for 2nd pick = 48 - 1 = 47

Pr(dime after a penny without replacement) = number of dime/total coin

Pr(dime after a penny without replacement) = 7/47

The probability of a penny and then without replacement a dime = Probability of picking a penny ×

Pr(dime after a penny without replacement)


\begin{gathered} Pr(penny,\text{ then a dime without replacement\rparen= }(6)/(48)*(7)/(47) \\ \\ Pr(penny,\text{ then a dime without replacement\rparen= }(1)/(8)*(7)/(47) \\ \\ Pr(penny,\text{ then a dime without replacement\rparen= }\frac{7}{376\frac{}{}} \\ \\ Pr(penny,\text{ then a dime without replacement\rparen= 0.0186} \end{gathered}

User Muenchdo
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