Question

A semicircular turn on a racetrack is 915 m long, and has a radius of 291 mWhat is the centripetal acceleration of a car that completes the turn at a constant speed in 15 s?

Answer 1

The centripetal acceleration is given by the formula

`a_c=(v^2)/(r)`

Here, r is the radius and is equal to 291 m

For finding the value of centripetal acceleration, first we need to find velcity v,

The formula for velocity is

`v=\frac{dis\tan ce\text{ }}{\text{time}}`

Substituting the values,

`v=(915)/(15)`

So the velocity is 61 m/s.

Now, the value of velocity will be substituted in the centripetal acceleration formula

`a_c=((61)^2)/(291)`

Hence the value of centripetal acceleration is 12.78 meter per second squared.