Question

a ball of mass 0.15 kg is attached to one end of a string 1.10 m long. the ball moves in a horizontal circle with a speed of 12 m/s. determine the magnitude of the tension in the string​

Answer 1

`19.64N`

Step-by-step explanation:

Let's remember that if a mass describes a circle of radius
`l` with a constant speed of
`v`, it has an angular velocity
`\omega=\frac vl`. in our case, our angular velocity will be of
`12/1.1= 10.91 rad/s`.

Now that same mass will be subject of a centripetal acceleration
`a_c`, caused of the tension of the string, equal to
`a_c=\omega^2l`, which, in our situation, will be
`(10.91)^2*1.1=130.91 m/s^2`

We're almost done. We got mass, we got acceleration, the tension has to be their product:
`T= ma=130.91*0.15=19.64N`