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36x² + 49y² = 1,764 the foci are located at:

User Aeronth
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1 Answer

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Given:


36x^2+49y^2=1764
(36x^2)/(1764)+(49y^2)/(1764)=(1764)/(1764)
(x^2)/(49)+(y^2)/(36)=1
(x^2)/(7^2)+(y^2)/(6^2)=1
a^2=49;b^2=36
c^2=a^2-b^2
c^2=49-36
c^2=13
c=\pm\sqrt[]{13}
(-\sqrt[]{13},0)\text{ \& (}\sqrt[]{13},0)\text{ are the focii of the given ellipse.}

User VBwhatnow
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