SOLUTION
We are told to find the equation of the line passing through the points (2, 5) and parallel to
![y=-(1)/(2)x-2](https://img.qammunity.org/2023/formulas/mathematics/college/8vx1b4b2qgotbvwvhzjbp4gr4akczaijly.png)
Now, equation of line in slope intercept form is given as
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
comparing this to
![y=-(1)/(2)x-2](https://img.qammunity.org/2023/formulas/mathematics/college/8vx1b4b2qgotbvwvhzjbp4gr4akczaijly.png)
We can see that m for that equation is
![-(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/g3dzahzg2weqewvw38ee4amnmv0vijzmvk.png)
m is the slope.
For two parallel lines, m1 = m2. That is their slopes are equal.
So we will use our m as
![m=-(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/6ks8rjuc16pambe301medyr3eb1cvqsxyv.png)
For equation of line for point and slope form, we have the formula as
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
using this, the equation of the line becomes
![\begin{gathered} y-y_1=m(x-x_1) \\ \\ y-5_{}=-(1)/(2)(x-2) \\ \\ y-5=-(x)/(2)+(2)/(2) \\ \\ y-5=-(x)/(2)+1 \\ \\ y=-(x)/(2)+6 \\ \\ y=-(1)/(2)x+6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/miq05ue9q8aqxsatjuwncfkuo86056gp00.png)
Therefore, option C is the correct answer