The given equation is:
![\begin{gathered} y=x^2-6x+6 \\ y=x^2-6x+9-3 \\ y+3=(x-3)^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/t8lwk941wd2kjuju6maqcdbx8bha1vj0z9.png)
Hence the vertex of the parabola is at (3,-3).
The two points to the left of the vertex of the parabola are (0,6) and (2.-2).
The two points to the right of the vertex of the parabola are (6,6) and (5.1).
The graph is shown below: