Question

Solve the following exponential equation:

5^x=2

e^x=10​

Answer 1

Number 1.

`5^x=2`, first we will take the
`log` of both of these numbers getting us,

`x=(log(2))/(log(5))`, which then gives us that
`x=0.4306777777....`

Number 2

`e^x=10`, solve for our exponent,
`2.718282^x=10`, use the logarithmic formula, and we get,

`x=(log(10))/(log(2.718282))`, which then we get that
`x=2.302585`