Question

An employee earns $10,000 in the first year in his job. Each year thereafter, the employee receives a raise of $500. How much the employee will get in 6th year? Use the explicit formula.$12,000$12,500$13,000$60,000

Answer 1

Since he will earn $10,000 in the first year

Since he will earn $500 more each year

Then it is an arithmetic sequence

The rule of the arithmetic sequence is

`a_n=a+(n-1)d`

a is the initial amount (10,000)

d is the constant increasing (500)

n is the time (6)

Substitute the values of a, d, and n in the explicit formula above to find how much he will earn in the 6th year

`\begin{gathered} a_6=10,000+(6-1)500 \\ \\ a_6=10,000+(5)500 \\ \\ a_6=10,000+2500 \\ \\ a_6=12,500 \end{gathered}`

The answer is $12,500

The answer is the 2nd choice