Question

may you please help me find the perimeter of the figure with the given verticies? (Round to the nearest tenth too please!)

Answer 1

Given

P(2,5)

Q(-3,0)

R(2,-5)

S(6,0)

Procedure

the perimeter of the figure:

The perimeter would be the sum of all the distances between the external shape points.

(2,5) -> (6,0)

`\begin{gathered} \sqrt[]{(6-2)^2+(5-0)^2} \\ 6.40 \end{gathered}`

(2,5) -> (-3, 0)

`\begin{gathered} \sqrt[]{(2--3)^2+(5-0)^2} \\ 7.07 \end{gathered}`

The total perimeter would be

`\begin{gathered} P=6.40\cdot2+7.07\cdot2 \\ P=26.94 \end{gathered}`

The perimeter would be 26.94