Question

If 103.6 J of heat energy was added to a gold ring with a mass of 128 g. What is thetotal temperature change for the gold ring? Assume the specific heat (c) of gold is 0.126 J/g°C. Round your answer to the nearest 0.1.

Answer 1

6.4 °C

Step-by-step explanation

Given:

Quantity of heat, Q = 103.6 J

Mass of the gold ring, m = 128 g

Specific heat, c of gold = 0.126 J/g°C

What to find:

The total temperature change (ΔT) for the gold ring.

Step-by-step soltion:

Using Q = mcΔT, the ΔT can be calculated

Pluging the values of the given parameters into the formula, we have

103.6 J = 128 g x 0.126 J/g°C x ΔT

103.6 J = 16.128 J/°C x ΔT

Divide both sides by 16.128 J/°C

ΔT = (103.6 J)/(16.128 J/°C)

ΔT = 6.4 °C

Therefor, hte total temperature change (ΔT) for the gold ring. = 6.4 °C