10 +5√2
To find the perimeter of a triangle, let's use a formula derived from the Pythagorean Theorem:
![d\text{ =}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/72jvgu5fosyt6cczkwbt9o4bdlur39l8j7.png)
2) So let's calculate the length of the segment AB. A(1,1) and B (4,-3)
![d=\sqrt[]{(4-1)^2+(-3-1)^2}=5](https://img.qammunity.org/2023/formulas/mathematics/college/wya5zvqs8mummzwa05u5kmkiqtl64v6q7z.png)
The segment BC , B(4,-3) and C(-3,-2):
![d=\sqrt[]{(-3-4)^2+(-2+3)^2}=5\sqrt[]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/qy4adobgf5w9lkx2funweqdrk5fb7akywo.png)
And finally, the segment AC: A(1,1) and C(-3,-2)
![d=\sqrt[]{(-3-1)^2+(-2-1)^2}=5](https://img.qammunity.org/2023/formulas/mathematics/college/m1kdg59s6kffdmlq5xb5i0md1oh0dhd9iu.png)
3) The Perimeter is the sum of the lengths: 5 + 5 +5√2 = 10 +5√2