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Find the equation of the line passing through the points (10,8) and (-10,30). Write your answer in the form

Find the equation of the line passing through the points (10,8) and (-10,30). Write-example-1
User Hutch
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The equation of a line in slope-intercept form is given by:


y=mx+b

Where m is the slope and b is the y-intercept.

We know two points on the line: (10,8) and (-10,30).

The slope can be found by using the following formula:


m=(y2-y1)/(x2-x1)

Where (x1,y1) and (x2,y2) are the coordinates of two points on the line. By replacing the known coordinates we obtain:


m=(30-8)/(-10-10)=(22)/(-20)=-(11)/(10)

The y-intercept can be found by replacing the slope and one of the points in the slope-intercept formula, and solving for b:


\begin{gathered} 8=-(11)/(10)\cdot10+b \\ 8=-11+b \\ 8+11=b \\ b=19 \end{gathered}

Thus, the equation of the line is:


y=-(11)/(10)x+19

User Mostafa Zeinali
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