The radius of the circle is = 13
This is because, the line from the center of the circle bisects the chord AB, as shown below:
Now consider any of the two right triangles obtained, and apply the pythagorean theorem:
Applying the pythagorean theorem to obtain r:
![\begin{gathered} r^2=5^2+12^2 \\ r^2=25^{}+144 \\ r^2\text{ = 169} \\ r\text{ =}\sqrt[]{169} \\ r\text{ = 13} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/l8xbnx2sbpoum4547vk0hxnaie5w4wzqrm.png)
Therefore, the radius of the circle is r = 13