Question

A projectile is fired vertically upward with an initial velocity of 190 m/s. Find the maximum height of the projectile

Answer 1

Height is equal to 1841.8367m

Step-by-step explanation:

KE = GPE

Write out the formula

1/2(m)(v^2) = mgh

Fill it with the information you have

1/2(190^2) = (9.8)(h)

Solve

1/2(36100) = 9.8h

18050 = 9.8h

1841.83673 = h

Write the complete answer out

Maximum height is equal to 1841.8367m (meters)

Answer 2

`1841.84\text{ m}`

EXPLANATION

Parameteters given:

Initial velocity = 190 m/s

To find the maximum height, we apply the formula for the maximum height of a projectile:

`H=(u^2\sin ^2\theta)/(2g)`

where u = initial velocity

θ = angle with the horizontal

g = acceleration due to gravity = 9.8 m/s²

From the question, the projectile is fired vertically upward. This means that the projectile will make a 90° angle with the horizontal.

Therefore, we have that the maximum height of the projectile is:

`\begin{gathered} H=(190^2\cdot\sin ^2(90))/(2\cdot9.8) \\ H=1841.84\text{ m} \end{gathered}`