Question

Sample and population standard deviationyou might need alculatorYou have found the following ages (in years) of 5 gorillas. Thosegorillas were randomly selected from the 29 gorilas at your local20058, 4, 14, 16, 8Based on your sample, what is the average age of the gorillas?What is the standard deviation Round your answers to thenearest tenth2010

Answer 1

Answer:

Step-by-step explanation:

The ages of the 5 sample of gorillas are:

8, 4, 14, 16, 8

The average age of the gorillas

`\begin{gathered} Average,\text{ \mu = }(8+4+14+16+8)/(5) \\ \\ \mu=(50)/(5) \\ \\ \mu=10 \end{gathered}`

The standard deviation of a sample is calculated with the formula:

`\begin{gathered} \sigma=\sqrt{(\sum_^(x_i-\mu)^2)/(N-1)} \\ \\ \sigma=\sqrt{((8-4)^2+(4-4)^2+(14-4)^2+(16-4)^2+(8-4)^2)/(5-1)} \\ \\ \sigma=\sqrt{(16+100+144+16)/(4)} \\ \\ \sigma=\sqrt{(276)/(4)} \\ \\ \sigma=√(69) \\ \\ \sigma=8.3 \end{gathered}`