Question

A container with 155 cm3 of chlorine gas exerts a pressure of 22.5 kPa. What will be the pressure if the volume is changed to 90.0 cm3, assuming the same temperature.

Answer 1

• V1=155cm^3
• V2=90cm^3
• P_1=22.5×10^3Pa
• P_2=?

Apply Boyle's law

`\\ \tt\longmapsto P_1V_1=P_2V_2`

`\\ \tt\longmapsto 155(22.5* 10^3)=90P_2`

`\\ \tt\longmapsto 3487500=90P_2`

`\\ \tt\longmapsto P_2=38.75kPa`