Question

What do i need to do

Answer 1

we know that "x" and "y" are encapsulating a function in "t" terms, so then we'll do implicit differentiation on the equation.

`x^2+3y=4\implies \stackrel{chain~rule}{2x\cdot \cfrac{dx}{dt}}+3\cfrac{dy}{dt}=0\implies 2x\cdot \cfrac{dx}{dt}=-3\cfrac{dy}{dt} \\\\\\ \\\stackrel{\textit{`