Question

A gas takes up a volume of 17 L, has a pressure of 3.4 atm and a temperature of 298K. If Ilower the temperature to 250 K and lower the pressure to 1.5 atm, what is the new volumeof the gas?

Answer 1

To answer this question, we have to use the combined law of gases, that states that:

`(P1V1)/(T1)=(P2V2)/(T2)`

Where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes and T1 and T2 are the initial and final temperatures. In this case, P1, V1, T1, P2 and T2 are given and we have to find V2:

`\begin{gathered} (3.4atm\cdot17L)/(298K)=(1.5atm\cdot V2)/(250K) \\ V2=(3.4atm\cdot17L\cdot250K)/(1.5atm\cdot298K) \\ V2=32.3L \end{gathered}`

It means that the new volume of the gas is 32.3 L, the correct answer is C.