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Given: ABCD is a parallelogram and AB is congruent to BCProve AC is perpendicular to BD

Given: ABCD is a parallelogram and AB is congruent to BCProve AC is perpendicular-example-1

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Answer

step statement Reason

2 BD bisect AC Diagonals of a parallelogram bisects each other

3 AE = EC A segment bisector divides a segment into two congruent segments

4 BE = DE A segment bisector divides a segment into two congruent segments

5 BE = BE A segment is congruent to itself

6 ΔABE = ΔCBE The three sides are congruent

7 ∠BEA = ∠BEC Corresponding parts of congruent triangles are congruent (CPCTC)

8 ∠BEA and ∠BEC are supplementary If two angles form a linear pair then they are supplementary.

9 ∠BEA = 90° ∠BEA = ∠BEC and they are supplementary

10 AC ⊥ BD They form an angle of 90°

Step-by-step explanation:

Since ABCD is a parallelogram, the diagonals bisect each other, so, we can start the prove as:

step statement Reason

2 BD bisect AC Diagonals of a parallelogram bisects each other

Then, AE = EC and BE = DE, so

step: 3

statement: AE = EC

Reason: A segment bisector divides a segment into two congruent segments

Step: 4

Statement: BE = DE

Reason: A segment bisector divides a segment into two congruent segments

Now, since AB = BC, AE = EC, and BE = BE, the triangles ABE and ACE are congruent, so:

step statement Reason

5 BE = BE A segment is congruent to itself

6 ΔABE = ΔCBE The three sides are congruent

Finally, if the triangles are congruent the corresponding angles are also congruent, so:

step statement Reason

7 ∠BEA = ∠BEC Corresponding parts of congruent triangles are congruent (CPCTC)

Additionally, these angles are supplementary because they form a straight line, so:

step: 8

statement: ∠BEA and ∠BEC are supplementary

Reason: If two angles form a linear pair then they are supplementary.

Therefore, if they sum 180 degrees and they are equal, the only option is that each one measures 90 degrees. So,

Step statement Reason

9 ∠BEA = 90° ∠BEA = ∠BEC and they are supplementary

10 AC ⊥ BD They form an angle of 90°

User Jim Driscoll
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