Question

Write the equation in standard form for the circle with center (0, 9) passing through (0, 27/2)

Answer 1

Given

coordinates of center= (0,9)

Circle passes through (0, 27/2)

Find

Equation of circle

Step-by-step explanation

The equation of circle in standard form is

`\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ (x-0)^2+(y-9)^2=r^2 \end{gathered}`

We know the circle passes through (0,27/2), then

`\begin{gathered} (0-0)^2+((27)/(2)-9)^2=r^2 \\ r=4.5 \end{gathered}`

So the equation in the standard form is

`(x-0)^2+(y-9)^2=4.5^2`

Final Answer

`(x-0)^2+(y-9)^2=4.5^2`