Question

Simplify 6x2y ÷ 3xy2 .2y2 z. x. xz

Answer 1

`(6x^2y)/(z)+(3xy^2)/(z)\cdot(2y^2)/(xz)`

first we solve the multiplication

`\begin{gathered} (6x^2y)/(z)+((3*2)x(y^2* y^2))/((z* z)x)^{} \\ (6x^2y)/(z)+(6xy^4)/(z^2x) \\ (6x^2y)/(z)+(6y^4)/(z^2) \end{gathered}`

now do the sum

`\begin{gathered} ((6x^2y* z^2)+(6xy^4* z))/((z* z^2)) \\ \\ \frac{6x^2z^2y+6y^4z^{}}{z^3} \\ \\ (6x^2y)/(z)+(6y^4)/(z^2) \end{gathered}`