
Step-by-step explanation
Step 1
find the slope of the line:
if you know 2 poitns(P1 and P2) of a lines, you can easily find the slope using:

then, pick 2 points from the line in the graph
Let
P1(0,10000)
P2(40,0)
replace,

Step 2
Now, find the equation of the line,using:

Let
P1(0,10000)
replace,

I hope this helps you