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Suppose a small fish species is introduced into a pond that had not previously held this type of fish, and that its population P, in thousands, is modeled by P=(3x+1)/(x+4) where x represents the time in months. i) Describe the overall trend of P as x goes to infinity. ii) how many fish were initially introduced into the pond? iii) this model is restricted to x>=0. Why?

User Or Bachar
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1 Answer

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i)When x goes to infinity we get:


\lim _(x\rightarrow+\infty)P(x)=\lim _(x\rightarrow+\infty)(3x+1)/(x+4)

Computing the limit we get:


\lim _(x\rightarrow+\infty)(3x+1)/(x+4)=\lim _(x\rightarrow+\infty)((3x)/(x)+(1)/(x))/((x)/(x)+(4)/(x))=\lim _(x\rightarrow+\infty)(3+(1)/(x))/(1+(4)/(x))=(3+0)/(1+0)=3

Therefore the fish population tends to 3,000 fishes as x goes to infinity.

ii) The initial population is:


P(0)=(3\cdot0+1)/(0+4)=(1)/(4)

which is equal to 1000/4=250 fishes.

iii) This model is restricted to x≥0 because there were no fishes of the same type in the pond before the introduction of the species.

User Prajwol Onta
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6.2k points
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