Consider a rectangular prism with length l, width w and height h;
Volume of rectangular prism = Length x width x height
![\text{Volume of the rectangular prism =lwh}](https://img.qammunity.org/2023/formulas/mathematics/college/mp216xaki9vex78sq01kpdeqi3oi41j68e.png)
Now, it is given that, If the width of a rectangular prism is doubled;
new width = 2w
the length is tripled, i,e
New length = 3l
The height is doubled i.e,
New height = 2h
The volume of the rectangular prism is;
![\begin{gathered} \text{Volume of new prism = length }*\text{width }*\text{ height} \\ \text{Volume of new prism =3l}*2w*2h \\ \text{Volume of new prism =}3*2*2lwh \\ \text{Volume of new prism =}12\text{lwh} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/erw33b1m5ep4ds2fm869nn4jpam56v10iw.png)
Since, volume of original prism is lwh
Thus,
![\begin{gathered} \text{Volume of new prism =}12\text{lwh} \\ \text{Volume of new prism =}12\text{Volume of original prism} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mf78hm5mmae4goyvko7937bosbp9bh3uqq.png)
Thus, the resulting volume of the prism is twelve times the original volume
Answer : C) twelve times the original volume