Question

5. When 62.7 g of nitrogen and excess oxygen react they generate nitrogen dioxide. If the NO2 is collected at 620 K and 0.72 atm, what volume will it occupy?___ N2 (g) + ___O2 (g) → ___ NO2 (g)

Answer 1

answer and explanation

the first step is to balance the reaction equation

N₂ + 2O₂ > 2NO₂

now that we have balanced the equation we can calculate the number of moles of nitrogen

mols = mass / molar mass

= 62.7 g/ 14.00g/mol

= 4.48 mols

we see from the balanced equation that the mol ratio of nitrogen and nitrogen oxide is 1:2

therefor the number of mols of nitrogen oxide that will form will be

2 x 4.48 = 8.96 mol of nitrogen oxide.

now that we have the mols we can then calculate the volume using the ideal gas equation

PV =nRT

V = (nRT)/P

= (8.96 x 0.0821 x 620) / 0.72

= 633.5L