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May I please get help with this for I have tried my times but still could not get them right?

May I please get help with this for I have tried my times but still could not get-example-1
User Urdearboy
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1 Answer

2 votes

Answer:


d=\frac{4}{\sqrt[]{3}},c=8\sqrt[]{2}

Step-by-step explanation:

Use the trigonometric ratio,


\sin \theta^{}=\frac{Opposite\text{ side}}{Hypotenuse}

From the first right angled triangle,


\begin{gathered} \sin 60^o=(2)/(d) \\ d=(2)/(\sin60^o) \\ =\frac{2}{\frac{\sqrt[]{3}}{2}} \\ =\frac{4}{\sqrt[]{3}} \end{gathered}

Similarly, from the second right angled triangle,


\begin{gathered} \sin 45^o=(8)/(c) \\ c=(8)/(\sin 45^o) \\ =\frac{8}{\frac{1}{\sqrt[]{2}}} \\ =8\sqrt[]{2} \end{gathered}
User Jasmine
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