Question

What is the solution to the equation below? 11 + 1-3x - 15 O AX=1 O B. X= 5 O c. x=-5 D. X-1

Answer 1

Starting with the given equation, substract 11 from each member:

`\begin{gathered} 11+\sqrt[]{1-3x}=15 \\ \Rightarrow11+\sqrt[]{1-3x}-1=15-11 \\ \Rightarrow\sqrt[]{1-3x}=4 \end{gathered}`

Raise both members to the power of 2:

`\begin{gathered} \Rightarrow(\sqrt[]{1-3x})^2=4^2 \\ \Rightarrow1-3x=16 \end{gathered}`

Solve for x:

`\begin{gathered} \Rightarrow-3x=16-1 \\ \Rightarrow-3x=15 \\ \Rightarrow x=(15)/(-3) \\ \Rightarrow x=-5 \end{gathered}`

Therefore, the answer is: