Question

Solve each system of the equation by elimination method. 2x+3y=258x+5y=37

Answer 1

x = -1 and y = 9

Step-by-step explanation:

Given the below system of equations;

`\begin{gathered} 2x+3y=25 \\ 8x+5y=37​ \end{gathered}`

To solve by using the elimination method, the 1st step is to multiply the 1st equation by 8 and the 2nd equation by 2, we'll have;

`\begin{gathered} 16x+24y=200 \\ 16x+10y=74 \end{gathered}`

The 2nd will be to subtract the 4th equation from the 3rd equation and solve for y;

`\begin{gathered} 0+14y=126 \\ y=(126)/(14) \\ y=9 \end{gathered}`

The 3rd step is to substitute y = 9 into the 1st equation and solve for x;

`\begin{gathered} 2x+3(9)=25 \\ 2x+27=25 \\ 2x=-2 \\ x=(-2)/(2)=-1 \end{gathered}`