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What is the average rate of change of the equation f(x)=x^2+3x-5 from x=2 to x=4

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The formula to calculate the average rate of change is as follows:


R=(f(b)-f(a))/(b-a)

Where "a" represents the starting point and "b" the ending point.

So, a = 2 and b = 4 in this case, so we have:


\begin{gathered} a=2 \\ f(a)=f(2)=2^2+3\cdot2-5=4+6-5=5 \\ b=4 \\ f(b)=f(4)=4^2+3\cdot4-5=16+12-5=23 \end{gathered}

Thus:


R=(23-5)/(4-2)=(18)/(2)=9

The average rate of change is 9.

User AndreyNik
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