Question

What volume will 2.90 moles of oxygen gas occupy at 25.0°C and 1.70 ATM pressure

Answer 1

The given value of the number of the moles is,

`n=2.9\text{ mol}`

The value of the temperature is,

`\begin{gathered} T=25^(\circ)C \\ T=25+273.15 \\ T=298.15\text{ K} \end{gathered}`

The value of the pressure is,

`\begin{gathered} P=1.7\text{ atm} \\ P=172253\text{ Pa} \end{gathered}`

By using the ideal gas equation,

`PV=\text{nRT}`

where R is the gas constant.

The value of the gas constant is,

`R=8.3145m^3PaK^(-1)mol^(-1)`

Substituting all the known values,

`\begin{gathered} 172253* V=2.9*8.3145*298.15 \\ V=0.042m^3 \end{gathered}`

Thus, the value of the volume occupied by the oxygen gas is 0.042 meter cube.