Answer:
A)
Given that,
On each trial, the machine outputs a ball with one of the digits 0 through 9 on it.
To find the probability of getting 6.
In each trail the probability of getting 6 is,

Let X be the event of getting 6.
we get

we get,

where n=50 and r=8
n is the total number of trials
r is the sucess trail.
Substitute the values we get,


Hence the required probability is,

On simplifying we get,

Answer is: 0.06