Question

For an object whose velocity in ft/sec is given by v(t) = -t^2 + 2, what is its displacement, in feet, on the interval t = 0 to t = 2 secs?

Answer 1

Given:

`v(t)=-t^2+2`

Required:

To calculate its displacement

Step-by-step explanation:

Velocity is the derivative of displacement with respect to time.

v=dx/dt

In this case , we have the velocity but need to know the displacement

We integrate the velocity function with the bounds of t=0 to t=2s

`\int_0^2t^2+2`

after calculating we get 1.333

Required answer:

Option A