Question

Find the equation of the linear function m that has m(-18) = 3 and that is parallel to f(a) = 5/11a +8.

Answer 1

`\begin{gathered} \text{if they are parallel then the slope for m is the same than for f.} \\ so\text{ we get that slope =5/11 and a point (-18,3) then} \\ y-3=(5)/(11)(x-(-18))=(5)/(11)(x+18) \\ y=(5)/(11)x+(90)/(11)-3=(5)/(11)x+(57)/(11) \end{gathered}`