Question

NATIONThe University of Central Florida's cheerleading team has eighteen males and twenty one females. If hrepresents the height of a teammember, the inequality 260 ≤ 4h + 28 < 324, represents the range of heights of the cheerleaders, in inches. Select all possible heights forthe University of Central Florida's cheerleaders.6 feet, 2 inches5 feet. 11 inches5 feet, 8 inches5 feet, 4 inches5 feet 3 inches4 feet, 10 inches4 feet, 9 inches

Answer 1

We have to solve the inequality for h (height)

260 ≤ 4h + 28 < 324

first, subtract 28 to all sides of the inequality:

260-28 ≤ 4h + 28 -28 < 324-28

232 ≤ 4h < 296

Then divide all sides by 4:

232/4 ≤ 4h /4 < 296/4

58≤ h < 74

So, the range of heights of the cheerleaders in inches is:

58 ≤ h < 74

To convert it into feet we have to divide by 12:

58/12= 4.83 feet = 4 feet and 10 inches

74/12= 6.16 feet = 6 feet and 2 inches

So:

4 feet and 10 inches ≤ h < 6 feet and 2 inches

The possible heights are:

5 feet. 11 inches

5 feet, 8 inches

5 feet, 4 inches

5 feet 3 inches

4 feet, 10 inches