1 Answer

Umlum · Answer 1 · 2023-10-10T17:22:15+0000

Given that the ratio of the radius of two distinct spheres is;

$3\colon4$

The surface area of a sphere is;

$A=4\pi* r^2$

Thus, the surface area of the first sphere is;

$\begin{gathered} A_1=4\pi(3)^2 \\ A_1=36\pi \end{gathered}$

Similarly, the surface area of the second sphere is;

$\begin{gathered} A_2=4\pi(4)^2 \\ _{}A_2=64\pi \end{gathered}$

Hence, the ratio of the surface areas is;

$(A_1)/(A_2)=(36\pi)/(64\pi)$

Reducing the fraction, we have;

$\begin{gathered} (A_1)/(A_2)=(9)/(16) \\ A_1\colon A_2=9\colon16 \end{gathered}$

CORRECT OPTION: C

Please log in or register to add a comment.