The given equation is
![2x+3y=7](https://img.qammunity.org/2023/formulas/mathematics/college/hgn72f4tjzh5p3ngqais40nhcsifm8qe0o.png)
To find a solution we must choose a value of x, then find the corresponding value of y
Let us choose x = 2
Substitute x in the equation by 2
![2(2)+3y=7](https://img.qammunity.org/2023/formulas/mathematics/college/a5nxl51ni6zq2c238w0hcwx7qzqicqx3au.png)
Then let us find the value of y
![4+3y=7](https://img.qammunity.org/2023/formulas/mathematics/college/mpxs2h2a2x0su8twkrdlps074kjplfpftv.png)
Subtract 4 from both sides
![\begin{gathered} 4-4+3y=7-4 \\ 3y=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/17n0jq2zkuuz3d837qwnzbydux11hfbuet.png)
Divide both sides by 3
![\begin{gathered} (3y)/(3)=(3)/(3) \\ y=1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/rxukt6b090lbotworz8rbsytbqfuje7dhf.png)
The solution is (2, 1)