Step-by-step explanation:
We can model the situation as:
So, we need to calculate the value of x.
Now, we know that the area will be increased by 200 m², so the initial area is:
25 m * 30 m = 750 m²
It means that the new area should be:
750 + 200 = 950 m²
Then, we know that the new area is also equal to the length times the width, so the new area is:
(25 + x + x) * (30 + x + x) = 950
Solving for x, we get:
![\begin{gathered} (25+x+x)\cdot(30+x+x)=950 \\ (25+2x)\cdot(30+2x)=950 \\ (25\cdot30)+(25\cdot2x)+(2x\cdot30)+(2x\cdot2x)=950 \\ 750+50x+60x+4x^2=950 \\ 4x^2+110x+750-950=0 \\ 4x^2+110x-200=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7p08psrmfua30td9kleq2vi48ns0wa9ynu.png)
Now, we have a quadratic function, so the solutions of the function can be calculated as:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
Where a is the number beside x², b is the number beside x and c is the constant.
Replacing, we get:
![\begin{gathered} x=\frac{-110\pm\sqrt[]{110^2-4\cdot4\cdot(-200)}}{2\cdot4} \\ x=1.71 \\ or \\ x=-29.21 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/tytwtbjaf2ghekbejiu65q59y0jkspnqoi.png)
Since x = -29.21 has no sense in this situation, the width of the strip is 1.71
Answer: 1.71 m