Question

Please help me find the answer to number three. With explanation.

Answer 1

`\begin{gathered} sin^\theta=\text{ }\frac{opposite\text{ side}}{hypotenuse} \\ sin(20º)=(19)/(x) \\ x\text{ = }(19)/(sin20) \\ \\ x=\text{ }(19)/(0.34) \\ \\ x\approx\text{ 55.8} \end{gathered}`

x=55.8

For right angles you always have to remember this:

`\begin{gathered} sin\theta=\text{ }\frac{opposite\text{ side}}{hypotenuse} \\ cos\theta=\text{ }\frac{adjacent\text{ side}}{hypotenuse} \\ tan\theta=\frac{adjacent\text{ side}}{opposite\text{ side}} \end{gathered}`