Question

What is the solution to the system below {5x+6y=14{3x+5y=7

Answer 1

Given data:

The first equation given is 5x+6y=14

The second equation given is 3x+5y=7.

Multiply first equation by 3 and second by 5 and then subtract second equation by first.

`\begin{gathered} 3(5x+6y)-5(3x+5y)=3(14)-5(7) \\ 15x+18y-15x-25y=42-35 \\ -7y=7 \\ y=-1 \end{gathered}`

Substitute -1 for y in the first equation.

`\begin{gathered} 5x+6(-1)=14 \\ 5x=20 \\ x=4 \end{gathered}`