If the triangle is a 45-45-90, then it must be an isosceles right triangle, therefore 15 must be equal to x, let's check that out using pythagorean theorem:
![\begin{gathered} (15\sqrt[]{2})^2=15^2+x^2 \\ x=\sqrt[]{(15\sqrt[]{2})^2-15^2} \\ x=\sqrt[]{450-225} \\ x=\sqrt[]{225} \\ x=15 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4lscd32pp187cefsatj8o9m1ffjqgyazv2.png)
Therefore, we can conclude that Tameka is correct. It is a 45-45-90 triangle.
Let's check the perimeter:
![P=15+15+15\sqrt[]{2}=30+15\sqrt[]{2}\\e45\sqrt[]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/kobm1a1n8oc1a6udi6byuf4lgcjk7dvmsi.png)
Thus, the only correct statements are:
B. Tameka is correct. It is a 45-45-90 triangle
D. The measure of the remaining leg is also 15