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Find the equation of a line that passes through the points (2,2) and (3,6).Leave your answer in the form y=mx+c

User JARP
by
8.3k points

1 Answer

3 votes

Solution

Step 1:

Write the coordinates (2,2) and (3,6).

Step 2:


\begin{gathered} Write\text{ the two points equation of a line formula} \\ \frac{y-y_1}{x\text{ - x}_1}\text{ = }\frac{y_2-\text{ y}_1}{x_2-\text{ x}_1} \end{gathered}

Step 3

Write the given value


\begin{gathered} x_1\text{ = 2} \\ y_1\text{ = 2} \\ x_2\text{ = 3} \\ y_2\text{ = 6} \end{gathered}

Step 4

Substitute in the formula


\begin{gathered} (y-2)/(x-2)=\text{ }(6-2)/(3-2) \\ (y-2)/(x-2)\text{ = }(4)/(1) \\ y\text{ - 2 = 4\lparen x - 2\rparen} \\ \text{y - 2 = 4x - 8} \\ y\text{ = 4x -8+ 2} \\ \text{y = 4x - 6} \end{gathered}

Final answer

y = 4x - 6

User Techdive
by
9.2k points

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