Question

This is part 3 of a problema block of 6kg hits a block of 5 kg, and they stick together.The first block has a speed of 3.14282 when it hits the second block

Answer 1

In order to calculate the final speed of both blocks together, we can use the equation for conservation of momentum:

`m_1v_1+m_2v_2=m_3v_3`

Where m3 in this case is the sum of m1 and m2.

So, using m1 = 6, m2 = 5, m3 = 11, v1 = 3.14282 and v2 = 0, let's calculate v3:

`\begin{gathered} 6\cdot3.14282+5\cdot0=11\cdot v_3 \\ 11v_3=6\cdot3.14282 \\ v_3=(6\cdot3.14282)/(11)=1.71427\text{ m/s} \end{gathered}`

Therefore the correct option is number 6.