Calculate the power of a heating coil that draws 11.0 A and has a resistance of 11.6 Ω.

asked Jul 4, 2023 32.6k views

4 votes

by Somum

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We will have the following:

$V=IR\Rightarrow V=(11.A)(11.6\Omega)$
$\Rightarrow V=127.6V$

So, the power of the heating coil is 127.6 V.

Cross Vander answered Jul 9, 2023

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