Question

4x^2-x-5 form and factorization

Answer 1

Factorise the equation

`4x^2-x-5`

Step 1: Break the expression into groups

`\begin{gathered} 4x^2-x-5 \\ 4x^2+4x-5x-5 \end{gathered}`

Step 2: factorise the expression

`\begin{gathered} 4x^2+4x-5x-5 \\ 4x(x+1)-5(x+1) \\ (x+1)(4x-5) \end{gathered}`

Therefore the answer is

`(x+1)(4x-5)`