Answer:
100.12*C
Step-by-step explanation:
Our solute is glycerin and the solvent is water.
1) Convert grams of the solute to moles:
n (moles)=Mass/Molar Mass => 1/92.1=0.01086 moles
2) Find molality from moles of solute and mass of solvent in Kg:
m (molality)=moles of solute/Kg solvent => 0.01086/0.0478=0.2272m
3) Finding the change boiling point (Bp) using molality times the Bp constant (the Bp constant of water is 0.512*C/m): 0.2272*0.512=0.116*C
4) Under 1 atm, the boiling point of water is exactly 100 and to find the new Bp, simply add the change Bp completed in step 3 with the boiling point of water: 100+0.116=100.116*C or 100.12*C
Hope this helps!