A spring stores 12 J when it is stretched by 16 cm. Calculate the spring constant.

asked Jun 8, 2023 172k views

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$\\ \rm\rightarrowtail W=Fx$

$\\ \rm\rightarrowtail 12=1.6F$

$\\ \rm\rightarrowtail F=7.5N$

Now

$\\ \rm\rightarrowtail F=-Kx$

$\\ \rm\rightarrowtail 7.5=-1.6k$

$\\ \rm\rightarrowtail k=-4.68N/m$

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