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Solve the following system equation7x+9y=95x+3y=-21x=y=

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\mleft\{\begin{aligned}7x+9y=9 \\ 5x+3y=-21\end{aligned}\mright.

We can solve this system by elimination. So we are goinf to multiply the first equation by 1 and the second one by -3. Just to have the same coefficient in the variable y:


\mleft\{\begin{aligned}7x+9y=9 \\ -15x-9y=63\end{aligned}\mright.

adding the equation we have that


\begin{gathered} -8x+0y=72 \\ x=-(72)/(8)=-9 \end{gathered}

if x=-9, we have that


\begin{gathered} 7\cdot-9+9\cdot y=9 \\ -63+9y=9 \\ 9y=72 \\ y=(72)/(9)=8 \end{gathered}

so x=-9 and y=8

User Jasiu
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