Question

Find a polynomial function of degree 3 with real coefficients that satisfies the given conditions. Zero of -2 having multiplicity​ 3; ​f(3​)=25.

Answer 1

Answer: f(x) = (1/8)(x + 5)3

Step-by-Step:

f(x) = a(x + 5)3

f(3) = a(3 + 5)3 = 64

a = 64 / 83 = 82 / 83 = 1/8